Question

(sqrt6-sqrt11)(sqrt6+sqrt11)

Answer 1

Ответ:

-5

Объяснение:

(a+b)(a-b)=a^2-b^2

6-11=-5

Answer 2

To simplify the given expression $(\sqrt{6} - \sqrt{11})(\sqrt{6} + \sqrt{11})$, you can use the difference of squares formula: $a^2 - b^2 = (a + b)(a - b)$.

In this case, let $a = \sqrt{6}$ and $b = \sqrt{11}$. Applying the difference of squares formula:

$(\sqrt{6} - \sqrt{11})(\sqrt{6} + \sqrt{11}) = (\sqrt{6})^2 - (\sqrt{11})^2$ $= 6 - 11$ $= -5$

So, $(\sqrt{6} - \sqrt{11})(\sqrt{6} + \sqrt{11}) = -5$.