Question

1. (1/2)^-2 √81 - 9 2. x^2-x-3=3

Answer 1

Ответ:

Я ещё не проходила это

Answer 2

Let's break down the two expressions step by step:

1. $(\frac{1}{2})^{-2} \sqrt{81} - 9$:

   First, let's simplify the exponent and the square root:

   $(\frac{1}{2})^{-2} = 2^2 = 4$ $\sqrt{81} = 9$

   Now we can substitute these values back into the original expression:

   $4 \cdot 9 - 9$ $36 - 9$ $27$

   So, the result of the expression is $27$.

2. $x^2 - x - 3 = 3$:

   To solve this quadratic equation for $x$, we need to bring all terms to one side and then factor or use the quadratic formula. Let's start by simplifying the equation:

   $x^2 - x - 3 - 3 = 0$ $x^2 - x - 6 = 0$

   Now we can try to factor the quadratic expression. Factoring is not always possible, but in this case, the quadratic factors nicely:

   $(x - 3)(x + 2) = 0$

   Now we can use the zero product property to find the possible values of $x$:

   $x - 3 = 0$ or $x + 2 = 0$

   Solving for $x$ in each equation:

   $x = 3$ or $x = -2$

   So, the solutions for the equation are $x = 3$ and $x = -2$.