Question

(2х-у)вквадрате+(2х-у) (х - у) ​

Answer 1

Ответ:

Объяснение:

(2х-у)²+(2х-у)(х-у)=4х²-4ху+у²+2х²-2ху-ху+у²=6х²-7ху+2у²

Answer 2

It seems like you want to expand the given expression $(2x - y)^2 + (2x - y)(x - y)$. Let's break it down step by step:

Given expression: $(2x - y)^2 + (2x - y)(x - y)$

First, let's expand $(2x - y)^2$: $(2x - y)^2 = (2x - y)(2x - y) = 4x^2 - 2xy - 2xy + y^2 = 4x^2 - 4xy + y^2$

Now, let's expand $(2x - y)(x - y)$: $(2x - y)(x - y) = 2x(x - y) - y(x - y) = 2x^2 - 2xy - xy + y^2 = 2x^2 - 3xy + y^2$

Now, let's put these two results together: $(2x - y)^2 + (2x - y)(x - y) = (4x^2 - 4xy + y^2) + (2x^2 - 3xy + y^2) = 6x^2 - 7xy + 2y^2$

So, the expanded form of the given expression is $6x^2 - 7xy + 2y^2$.