Question

1. (12у+30)(1,4-0,7у) =0​

Answer 1

Ответ:

(12у+30)(1,4-0,7у) = 0

12y+30 = 0;          1.4-0.7y = 0

12y = -30;              -0.7y = -1.4

y = -2.5;                  y = 2

Answer 2

Пишу сразу решение

$(12 + y) \times (\frac{7}{5} - \frac{7}{10} y) = 0 \\ \\ 12 y + 30 = 0 \\ \\ \frac{7}{5} - \frac{7}{10} y = 0 \\ \\ y = - \frac{5}{2} \\ y = 2 \\ \\ y1 = - \frac{5}{2} = - 2.5 \\ \\ y2 = 2$

Answer 3

To solve the equation (12у + 30)(1.4 - 0.7у) = 0, we need to find the values of у that satisfy the equation.

The equation is set to zero, which means one or both of the factors must be equal to zero. Therefore, we have two possibilities:

1. Setting 12у + 30 = 0: 12у + 30 = 0 12у = -30 у = -30/12 у = -2.5

2. Setting 1.4 - 0.7у = 0: 1.4 - 0.7у = 0 -0.7у = -1.4 у = -1.4/-0.7 у = 2

So, the equation (12у + 30)(1.4 - 0.7у) = 0 is satisfied when у = -2.5 or у = 2.