Question

1) 5-2x = 11-7(x+2) 2) 10x+9=7x3) 10(x-9)=74) 1-5x= -6x+85) 9-2(-4x + 7) = 7

Answer 1

Ответ:

1) х=-1,6

2)х=-3

3)х=-30

4)х=7

5)х=1,5

Объяснение:

1)

5-2х=11-7(х+2)

-2х=11-5-7х-14

7х-2х=11-5-14

5х=-8

х=-8/5

х=-1,6

2)

10х+9=7х

10х-7х=-9

3х=-9

х=-3

3)

10(х+9)=7х

10х+90-7х=0

3х=-90

х=-90/3

х=-30

4)

1-5х=-6х+8

-5х+6х=8-1

х=7

5)

9-2(-4х+7)=7

9+8х-14=7

8х=7-9+14

8х=12

х=12/8

х=1,5

Answer 2

It looks like you've provided five different linear equations. If you'd like, I can help you solve them one by one:

1. $5 - 2x = 11 - 7(x + 2)$:

First, distribute the -7 on the right side: $5 - 2x = 11 - 7x - 14$

Combine like terms: $5 - 2x = -3 - 7x$

Add $7x$ to both sides: $7x - 2x = -3 - 5$ $5x = -8$

Divide by 5: $x = -\frac{8}{5}$

2. $10x + 9 = 7x$:

Subtract $7x$ from both sides: $10x - 7x = -9$ $3x = -9$

Divide by 3: $x = -3$

3. $10(x - 9) = 7$:

Distribute the 10: $10x - 90 = 7$

Add 90 to both sides: $10x = 97$

Divide by 10: $x = \frac{97}{10}$

4. $1 - 5x = -6x + 8$:

Add $6x$ to both sides: $1 + x = 8$

Subtract 1 from both sides: $x = 7$

5. $9 - 2(-4x + 7) = 7$:

Distribute the -2 inside the parentheses: $9 + 8x - 14 = 7$

Combine like terms: $8x - 5 = 7$

Add 5 to both sides: $8x = 12$

Divide by 8: $x = \frac{12}{8}$ $x = \frac{3}{2}$

So, the solutions for each equation are:

1. $x = -\frac{8}{5}$
2. $x = -3$
3. $x = \frac{97}{10}$
4. $x = 7$
5. $x = \frac{3}{2}$