Question

1) 6a3ab-7a4ab-18ab2a-3ab²=2)½a²+⅓b²-(5/2a²-3/2 b²)+(a²-b²)​=

Answer 1

Ответ:

1) -46a²b-3ab²

2)незн

Answer 2

To simplify these expressions, let's break them down step by step:

1. $6a^3b - 7a^4b - 18ab^2a - 3ab^2 =$ Factor out common terms from each term: $ab$ is common to all terms. $ab(6a^2 - 7a^3 - 18ba - 3b) =$ Simplify: $ab(6a^2 - 7a^3 - 18ab - 3b)$

2. $\frac{1}{2}a^2 + \frac{1}{3}b^2 - \left(\frac{5}{2}a^2 - \frac{3}{2}b^2\right) + (a^2 - b^2) =$ Distribute the negative sign inside the parentheses: $\frac{1}{2}a^2 + \frac{1}{3}b^2 - \frac{5}{2}a^2 + \frac{3}{2}b^2 + a^2 - b^2 =$ Combine like terms: $\left(\frac{1}{2}a^2 - \frac{5}{2}a^2 + a^2\right) + \left(\frac{1}{3}b^2 + \frac{3}{2}b^2 - b^2\right) =$ $\frac{1}{2}a^2 - \frac{5}{2}a^2 + a^2 + \frac{1}{3}b^2 + \frac{3}{2}b^2 - b^2 =$ $-\frac{3}{2}a^2 + \frac{5}{6}b^2$

So, the simplified forms of the given expressions are:

1. $ab(6a^2 - 7a^3 - 18ab - 3b)$
2. $-\frac{3}{2}a^2 + \frac{5}{6}b^2$