Question

Sin2a*cos2a help!!!!!!!

Answer 1

Упростить: Sin2a*cos2a.

Решение : применим формулу двойного аргумента 2sina*cosa =sin2a. Поэтому :

sin2a*cos2a =(sin4a)/2.

Answer 2

$Sin2\alpha *Cos2\alpha=\frac{1}{2}*2*Sin2\alpha*Cos2\alpha=0,5Sin4\alpha$

Answer 3

It seems like you're looking for help with trigonometric identities involving sine and cosine functions. Specifically, you want assistance with the expression sin(2a) * cos(2a). To solve this, you can use trigonometric identities.

One identity that might be helpful here is the double angle identity for sine:

sin(2θ) = 2 * sin(θ) * cos(θ)

In your case, let θ = a. Then, the expression becomes:

sin(2a) * cos(2a) = 2 * sin(a) * cos(a) * cos(2a)

Now, you might need to use another identity, which is the double angle identity for cosine:

cos(2θ) = cos²(θ) - sin²(θ)

In your case, θ = a:

cos(2a) = cos²(a) - sin²(a)

Now substitute this back into the earlier expression:

2 * sin(a) * cos(a) * cos(2a) = 2 * sin(a) * cos(a) * (cos²(a) - sin²(a))

At this point, you can simplify using basic algebraic manipulations. Remember that sin²(a) + cos²(a) = 1, which is the Pythagorean identity.

I hope this helps you simplify the expression sin(2a) * cos(2a)! If you need further assistance or clarification, feel free to ask.