Question

×2-(×-7)(×+7)=5-2(-2-×)​

Answer 1

Ответ:

20

Объяснение:

x²-(x-7)(x+7)=5-2(-2-x)

x²-x²+49=5+4+2x

x=20

Answer 2

To solve this equation, you can follow these steps:

1. First, expand both sides of the equation:

On the left side, expand the expression: 2x - (x^2 - 49)

On the right side, distribute the -2 to both terms inside the parentheses: 5 - 2(-2) + 2x

2. Now, simplify the equation:

2x - (x^2 - 49) = 5 - 2(-2) + 2x

3. Continue simplifying:

2x - x^2 + 49 = 5 + 4 + 2x

4. Rearrange the equation to group like terms:

x^2 - 2x - 49 + 2x - 2x = 5 + 4

5. Combine like terms:

x^2 - 49 = 9

6. Add 49 to both sides to isolate the x^2 term:

x^2 - 49 + 49 = 9 + 49

7. Simplify:

x^2 = 58

8. Take the square root of both sides (remembering to consider both the positive and negative square roots):

x = ±√58

So, the solutions for the equation are:

x = √58 and x = -√58.

Answer 3

To solve the equation $2x - (x - 7)(x + 7) = 5 - 2(-2 - x)$, you can follow these steps:

1. First, simplify both sides of the equation:

   $2x - (x^2 - 49) = 5 + 4 + 2x$

2. Distribute the negative sign through the parentheses on the left side:

   $2x - x^2 + 49 = 9 + 2x$

3. Move all terms to one side of the equation:

   $2x - x^2 + 49 - 9 - 2x = 0$

4. Combine like terms:

   $-x^2 + 40 = 0$

5. To isolate $x^2$, subtract 40 from both sides:

   $-x^2 = -40$

6. Now, multiply both sides by -1 to solve for $x^2$:

   $x^2 = 40$

7. Finally, take the square root of both sides to find the values of $x$:

   $x = ±√40$

So, the solutions for $x$ are $x = √40$ and $x = -√40$, or in decimal form, approximately $x = ±6.3246$.