Question

2^ 2-log2(5) + (1/2)^ log2(5)

Answer 1

Ответ:

= 1

Объяснение:

найти значение выражения:

${2}^{2 - log_{2}5} + {( \frac{1}{2}) }^{ log_{2}5} =$

1).

${2}^{2 - log_{2}5 } = \frac{ {2}^{2} }{ {2}^{ log_{2}5}} = \frac{4}{5} = 0.8$

2).

${( \frac{1}{2})}^{ log_{2}5} = {( {2}^{ - 1}})^{ log_{2}5} = {2}^{ - 1 \times log_{2}5} = {2}^{ log_{2} {5}^{ - 1}} = {5}^{ - 1} = \frac{1}{5} = 0.2$

3). 0,8+0,2=1

Answer 2

Let's break down the expression step by step:

1. 2^2 is equal to 4.

2. Now, let's consider the second part of the expression: -log2(5).

   • The logarithm base 2 of 5 is approximately 2.322.

3. The third part of the expression is (1/2)^log2(5).

   • We've already calculated that log2(5) is approximately 2.322.
   • So, (1/2)^log2(5) is equal to 0.5^2.322.

Now, let's calculate the third part:

0.5^2.322 ≈ 0.185

Now, we can put it all together:

4 - 2.322 + 0.185 ≈ 1.863

So, the value of the expression is approximately 1.863.