
2х³+mx²+13x+n=0m,n,x=? x1=2x2=3


Ответы на вопрос

2х³+mx²+13x+n=0
m,n,x=?
x1=2
x2=3
-------
x1 = 2
2*2³ + m*2² + 13*2 + n = 0
16 + 4m + 26 + n = 0
4m + n = - 42
x2 = 3
2*3³ + m*3² + 13*3 + n = 0
54 + 9m + 39 + n = 0
9m + n = -93
5m = -51
m = -10.2
4*(-10.2) + n = -42
n = -1.2
2(x - 2)(x - 3)(x - 0.1) = 0
x3 = 0.1
m,n,x= -10.2, -1.2, 0.1



To find the values of m, n, and x when you have the equations:
First, let's use the given values of and to set up a system of equations:
When :
When :
Now, let's solve this system of equations to find the values of m and n:
Now, we have the following equations:
We can solve this system of equations simultaneously. Subtracting the first equation from the second equation eliminates n:
Simplify:
Now, divide both sides by 5 to solve for m:
Now that we have found the value of m, we can substitute it back into one of the equations to solve for n. Using the first equation:
Now, isolate n:
To simplify the fraction on the right-hand side, find a common denominator:
So, the values of m and n are:
Now, we have the values of m and n. If you also need to find x, you can use either equation 1 or 2 to solve for x. Let's use equation 1:
Plugging in the values of m and n:
This is a cubic equation, and solving it for x might require numerical methods or a graphing calculator. You can approximate the solutions or use appropriate software to find the roots of the equation.


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