Question

(x-2y/x+2y-x+2y/x-2y):4xy/x^2-4y^2

Answer 1

Ответ:

Ответ на картинке.

Оформляйте нормально, умоляю!

Объяснение:

Answer 2

:::Ответ::::

-2

Объяснение:

Answer 3

Let's break down the expression step by step and simplify it:

Given expression:

$$\frac{\left(\frac{x - 2y}{x + 2y}\right) - \left(\frac{x + 2y}{x - 2y}\right)}{4xy} \div \frac{x^2 - 4y^2}{4xy}$$

Step 1: Simplify the numerator inside the first fraction:

$$\frac{\left(\frac{x - 2y}{x + 2y} - \frac{x + 2y}{x - 2y}\right)}{4xy}$$

Step 2: Find a common denominator for the fractions in the numerator:

$$\frac{\frac{(x - 2y)(x - 2y) - (x + 2y)(x + 2y)}{(x + 2y)(x - 2y)}}{4xy}$$

Step 3: Simplify the numerator further:

$$\frac{\frac{x^2 - 4y^2 - (x^2 + 4y^2)}{x^2 - 4y^2}}{4xy}$$

Step 4: Simplify the numerator and denominator:

$$\frac{\frac{-8y^2}{x^2 - 4y^2}}{4xy} = \frac{-2y^2}{x^2 - 4y^2}$$

Step 5: Now, we'll divide by the fraction in the denominator:

$$\frac{-2y^2}{x^2 - 4y^2} \div \frac{x^2 - 4y^2}{4xy}$$

Step 6: Invert the denominator and multiply:

$$\frac{-2y^2}{x^2 - 4y^2} \times \frac{4xy}{x^2 - 4y^2} = \frac{-8x^2y^3}{(x^2 - 4y^2)^2}$$

So, the simplified expression is:

$$\frac{-8x^2y^3}{(x^2 - 4y^2)^2}$$