Question

(6, 3x³y-3y²-0, 7 x) 10x²y2​

Answer 1

Ответ:

Если там 10х^2у^2

то:

6,3х^3у•10х^2у^3=63х^5у^3

3у^2•10х^2у^2=30х^2у^4

0,7х•10х^2у^2=7х^3у^2

Ответ: 63х^5у^3 - 30х^2у^4 - 7х^3у^2

Answer 2

It appears you have an expression that consists of three terms within parentheses, and you want to multiply this expression by $10x^2y^2$. To do this, you'll distribute the $10x^2y^2$ to each term within the parentheses. Here's how you can do it step by step:

The expression is: $(6, 3x^3y-3y^2-0, 7x) \cdot 10x^2y^2$

First, distribute $10x^2y^2$ to each term inside the parentheses:

$(6 \cdot 10x^2y^2, (3x^3y-3y^2-0) \cdot 10x^2y^2, 7x \cdot 10x^2y^2)$

Now, simplify each of these terms:

1. $6 \cdot 10x^2y^2 = 60x^2y^2$

2. $(3x^3y-3y^2-0) \cdot 10x^2y^2$ Distribute $10x^2y^2$ to each term inside the parentheses: $(3x^3y \cdot 10x^2y^2) - (3y^2 \cdot 10x^2y^2) - (0 \cdot 10x^2y^2)$ Simplify each term: $30x^5y^3 - 30x^2y^4 - 0$ This simplifies to: $30x^5y^3 - 30x^2y^4$

3. $7x \cdot 10x^2y^2$ Multiply the constants and add the exponents of $x$ and $y$: $70x^{1+2}y^{1+2} = 70x^3y^3$

Now, you have simplified each term:

$60x^2y^2, 30x^5y^3 - 30x^2y^4, 70x^3y^3$

These are the simplified terms after multiplying the original expression by $10x^2y^2$.