Question

X²-5x+6=05(x-2)=(3x+2)(x-2)​

Answer 1

Объяснение:

Відповідь зазначена на фотографії

Answer 2

It looks like you're presenting an equation. To solve it, we'll first need to simplify and then find the values of $x$ that satisfy the equation.

Let's break it down step by step:

1. Expand the equation: $x^2 - 5x + 6 = 0.5(x - 2) = (3x + 2)(x - 2)$

2. Distribute 0.5 to $x - 2$: $x^2 - 5x + 6 = 0.5x - 1$

3. Distribute the binomials $(3x + 2)(x - 2)$: $x^2 - 5x + 6 = 0.5x - 1 = 3x^2 - 4x - 4$

Now, the equation is: $x^2 - 5x + 6 = 0.5x - 1 = 3x^2 - 4x - 4$

4. Combine like terms: $x^2 - 5x + 6 - 0.5x + 1 - 3x^2 + 4x + 4 = 0$ $2x^2 - 4x + 11 = 0$

Now, you can use the quadratic formula to solve for $x$: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

For this equation ($2x^2 - 4x + 11 = 0$), the coefficients are $a = 2$, $b = -4$, and $c = 11$.

Plugging these values into the quadratic formula, the solutions for $x$ will be complex numbers because the discriminant ($b^2 - 4ac$) is negative. The solutions will be of the form: $x = \frac{4 \pm i\sqrt{36}}{4}$ $x = \frac{4 \pm 6i}{4}$

So the solutions for $x$ are: $x = 1 + \frac{3}{2}i \quad \text{and} \quad x = 1 - \frac{3}{2}i$

These are the complex solutions for the given equation.