Question

2cosп/3+5tg^2 п/4+ctgп/4+6sinп/6

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

It seems like you've written an expression with various trigonometric functions and values for an angle that looks like "п" (which I assume is supposed to be the Greek letter "π" or pi). Let's break down and simplify this expression step by step:

1. 2cos(п/3): This is the cosine of π/3.

2. 5tg^2(п/4): This appears to be the square of the tangent of π/4.

3. ctg(п/4): This is the cotangent of π/4.

4. 6sin(п/6): This is the sine of π/6.

Now, let's calculate each part:

1. cos(π/3) = 1/2 (cosine of π/3).

2. tg(π/4) = 1 (tangent of π/4), so tg^2(π/4) = 1^2 = 1.

3. ctg(π/4) = 1 (cotangent of π/4).

4. sin(π/6) = 1/2 (sine of π/6).

Now, substitute these values into the original expression:

2(1/2) + 5(1) + 1 + 6(1/2)

Now simplify:

1 + 5 + 1 + 3

Finally:

1 + 5 + 1 + 3 = 10

So, the simplified value of the given expression is 10.