Question

(3x-7)(10x+1)=(10x+1)²​

Answer 1

Ответ:

x = 8/157

Объяснение:

30x+3x-70x+1=10x+1+10x+1

-37x-7=120x+1

-37x-120x=8

-157x=8

x=8/157

Answer 2

To solve the equation (3x - 7)(10x + 1) = (10x + 1)², you can follow these steps:

1. Expand both sides of the equation: (3x - 7)(10x + 1) = (10x + 1)²

   Expanding the left side: 30x^2 + 3x - 70x - 7 = 100x^2 + 20x + 1

2. Simplify the expressions on both sides of the equation: 30x^2 - 67x - 7 = 100x^2 + 20x + 1

3. Move all terms to one side of the equation to set the equation to zero: 30x^2 - 67x - 7 - 100x^2 - 20x - 1 = 0

4. Combine like terms: (30x^2 - 100x^2) - (67x + 20x) - (7 + 1) = 0 -70x^2 - 87x - 8 = 0

5. Now, you have a quadratic equation in the form of ax² + bx + c = 0: -70x^2 - 87x - 8 = 0

6. To solve this quadratic equation, you can use the quadratic formula: x = (-b ± √(b² - 4ac)) / (2a)

   In this case, a = -70, b = -87, and c = -8.

   x = (87 ± √((-87)² - 4(-70)(-8))) / (2(-70)) x = (87 ± √(7569 - 2240)) / (-140) x = (87 ± √5329) / (-140) x = (87 ± 73) / (-140)

7. Solve for both solutions: x₁ = (87 + 73) / (-140) = 160 / (-140) = -8/7 x₂ = (87 - 73) / (-140) = 14 / (-140) = -1/10

So, the solutions to the equation (3x - 7)(10x + 1) = (10x + 1)² are x₁ = -8/7 and x₂ = -1/10.