Question

8(2x+y)-2y=-76 4(x-3y)+10y=-12

Answer 1

00000000000000000000000000000

Answer 2

To solve this system of linear equations, you can use the method of substitution or elimination. I'll use the elimination method here.

The system of equations is:

1. 8(2x + y) - 2y = -76
2. 4(x - 3y) + 10y = -12

Let's start by simplifying the equations:

1. 16x + 8y - 2y = -76
2. 4x - 12y + 10y = -12

Now, further simplify:

1. 16x + 6y = -76
2. 4x - 2y = -12

Now, we can use either the elimination method or the substitution method. I'll use the elimination method.

Multiply the second equation by 4 to make the coefficients of 'x' in both equations equal:

1. 16x + 6y = -76
2. 16x - 8y = -48

Now, subtract equation (2) from equation (1):

(16x + 6y) - (16x - 8y) = (-76) - (-48)

This simplifies to:

16x + 6y - 16x + 8y = -76 + 48

Combine like terms:

14y = -28

Now, divide both sides by 14 to solve for 'y':

y = -28 / 14 y = -2

Now that you have found the value of 'y,' you can substitute it back into one of the original equations to solve for 'x.' I'll use equation (1):

16x + 6(-2) = -76

Simplify:

16x - 12 = -76

Add 12 to both sides:

16x = -76 + 12 16x = -64

Now, divide both sides by 16 to solve for 'x':

x = -64 / 16 x = -4

So, the solution to the system of equations is:

x = -4 y = -2