Question

2a*(3a-5)-(a-3)*(a-7)=Спростити вираз​

Answer 1

Объяснение:

$2a \times (3a - 5) - (a - 3) \times (a - 7) = 6a {}^{2} - 10a - (a - 3)(a -7 ) = 6a {}^{2} - 10a - (a {}^{2} - 7a - 3a + 21) =6a^{2}-10a-\left(a^{2}-10a+21\right) =6a^{2}-10a-a^{2}-\left(-10a\right)-21 =6a^{2}-10a-a^{2}+10a-21 =5a^{2}-10a+10a-21 =5a^{2}-21$

Answer 2

Simplifying the Expression

To simplify the expression 2a*(3a-5)-(a-3)*(a-7), we can follow the order of operations (PEMDAS/BODMAS) and apply the distributive property. Let's break it down step by step:

1. Distribute the multiplication: - 2a*(3a-5) = 6a^2 - 10a - (a-3)*(a-7) = a^2 - 7a - 3a + 21 = a^2 - 10a + 21

2. Combine like terms: - 6a^2 - 10a - (a^2 - 10a + 21) = 6a^2 - 10a - a^2 + 10a - 21

3. Simplify the expression further: - 6a^2 - a^2 - 10a + 10a - 10a - 21 = 5a^2 - 21

Therefore, the simplified expression is 5a^2 - 21.