Question

Срочно . Решите уравнение: 1) x ^ 2 - 36 = 0 ; 2) 1 4 -x^ 2 =0; 3) 4x ^ 2 + 4x + 1 = 0 ; 4) 25 - 10x + x ^ 2 = 0

Answer 1

Объяснение:

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Answer 2

1. x^2 - 36 = 0

To solve this equation, we can factor the left side:

(x - 6)(x + 6) = 0

Setting each factor equal to zero, we have:

x - 6 = 0 => x = 6 x + 6 = 0 => x = -6

Therefore, the solutions to the equation are x = 6 and x = -6.

2. 14 - x^2 = 0

To solve this equation, we can rearrange it to isolate the variable:

x^2 = 14

Taking the square root of both sides, we have:

x = ±√14

Therefore, the solutions to the equation are x = √14 and x = -√14.

3. 4x^2 + 4x + 1 = 0

To solve this equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For this equation, a = 4, b = 4, and c = 1. Substituting these values into the formula:

x = (-4 ± √(4^2 - 4(4)(1))) / (2(4)) x = (-4 ± √(16 - 16)) / 8 x = (-4 ± √0) / 8 x = (-4 ± 0) / 8

The discriminant (b^2 - 4ac) is zero, which means there is only one solution:

x = -4/8 = -1/2

Therefore, the solution to the equation is x = -1/2.

4. 25 - 10x + x^2 = 0

To solve this equation, we can rearrange it to a quadratic form:

x^2 - 10x + 25 = 0

Now, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For this equation, a = 1, b = -10, and c = 25. Substituting these values into the formula:

x = (-(-10) ± √((-10)^2 - 4(1)(25))) / (2(1)) x = (10 ± √(100 - 100)) / 2 x = (10 ± √0) / 2 x = (10 ± 0) / 2

The discriminant is zero, which means there is only one solution:

x = 10/2 = 5

Therefore, the solution to the equation is x = 5.