Question

Y3+4y2-9y-36=0 CРОЧНО ПОЖАЛУЙСТА

Answer 1

Ответ:

у1=-4,у2=-3,у3=3

Объяснение:

у²(у+4)-9(y+4)=0

(y+4)(y²-9)=0

y+4=0

y²-9=0

у1=-4

у2=-3

у3=3

Answer 2

Ответ:

3y+8y-9y-36=0

2y-36=0

2y=36

y=18

Answer 3

Solving the Quadratic Equation Y^3 + 4Y^2 - 9Y - 36 = 0

To solve the quadratic equation Y^3 + 4Y^2 - 9Y - 36 = 0, we can use the quadratic formula or factorization method.

Using the Quadratic Formula

The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by: x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, the coefficients are: a = 1, b = 4, and c = -36.

Plugging these values into the quadratic formula, we get: Y = (-4 ± √(4^2 - 4*1*(-36))) / (2*1)

Solving this equation will give us the values of Y.

Factoring the Quadratic Equation

Another method to solve the quadratic equation is by factoring. We can factor the given equation Y^3 + 4Y^2 - 9Y - 36 = 0 and then solve for Y.

Let's proceed with solving the equation using the quadratic formula:

Y = (-4 ± √(4^2 - 4*1*(-36))) / (2*1) Y = (-4 ± √(16 + 144)) / 2 Y = (-4 ± √160) / 2 Y = (-4 ± 4√10) / 2 Y = -2 ± 2√10

So, the solutions to the equation Y^3 + 4Y^2 - 9Y - 36 = 0 are: Y = -2 + 2√10 and Y = -2 - 2√10.