Question

ПОМОГИТЕ ПОЖАЛУЙСТА СРОЧНО! 1. преобразуйте в многочленa)(a-4)²=б)(5у-с)²=в)(3а-5)³=г)(х²+2у)(х²-2у)=2.разложите на множители а)0,64-с²=б)а²+18а+81=в)х³-125=3.найдите значение выражения(а-2)²+3(а-4) при а = 2,14. выполните действияа)(1+3ху)(1-3ху)б)(2а+б)²-(2а-б)2в)(х²-у³)²г)64х³+(х-у)³+3ху(х-у)5.решите уравнениеа)3х²-48=0б)5х(х-3)²-5(х-1)³+15(х+2)(х-2)=5СРОЧНО ПОЖАЛУЙСТА​

Answer 1

Объяснение:

вот 2 сам сделай пожалуйста

Answer 2

Ответ:

1. а) а2-8а+16

б) 25у²-10ус+с²

в) 18а³-90а+225а-125

г) х⁴-2ух²+2ух²-4у²=x⁴-4y²

2. a) (0,8-c)(0,8+c)

б) (а+9)²

в) (х-5)(х²+5х+25)

3. (2,1-2)²+3(2,1-4)= 4,41-8,4+4+6,3-12=-5,69

4. а) 1-9х²у²

б)4а²+4аб+б²-4а+2б

в) х⁴-2х²у³+у⁶

г) 64х³+х³-3х²у+3ху²-у³= 65х³-3х²у+3ху²-у³

5. а)3х²=48

х²=48/3

х²=16

х=±√16

х=±4

х1=4;х2=-4

б)5х(х²-6х+9)-5(х³-3х²+3х-1)+15х²-60=5

5х³-30x²+4x-5x³+15x²-15x+5+15x²=65

↑(/) ↑(//) ↑(/) ↑(//) ↑(//)

-11x=60

x=60/(-11)

x=5×(6/11-дробью)

Answer 3

Factoring Expressions

a) (a-4)²: To expand the expression (a-4)², we can use the formula for the square of a binomial: (a-b)² = a² - 2ab + b². In this case, a = a and b = 4. Therefore, the expansion is: (a-4)² = a² - 2 * a * 4 + 4² = a² - 8a + 16.

b) (5y-c)²: Expanding (5y-c)², we use the same formula: (a-b)² = a² - 2ab + b². Here, a = 5y and b = c. Thus, the expansion is: (5y-c)² = (5y)² - 2 * 5y * c + c² = 25y² - 10yc + c².

c) (3a-5)³: Expanding (3a-5)³ involves using the formula for the cube of a binomial: (a-b)³ = a³ - 3a²b + 3ab² - b³. Substituting a = 3a and b = 5, we get: (3a-5)³ = (3a)³ - 3 * (3a)² * 5 + 3 * 3a * 5² - 5³ = 27a³ - 135a² + 225a - 125.

d) (x²+2y)(x²-2y): To factorize (x²+2y)(x²-2y), we recognize this as a difference of squares, which can be factored as (a² - b²) = (a+b)(a-b). Therefore: (x²+2y)(x²-2y) = (x²)² - (2y)² = (x²+2y)(x²-2y).

Factoring Quadratic and Cubic Expressions

a) 0.64-c²: The expression 0.64-c² can be factored using the difference of squares formula: a² - b² = (a+b)(a-b). In this case, a = 0.8 and b = c. Thus: 0.64-c² = (0.8+c)(0.8-c).

b) a²+18a+81: The expression a²+18a+81 can be factored as a perfect square trinomial: (a+b)² = a² + 2ab + b². Here, a = a and b = 9. Therefore: a²+18a+81 = (a+9)².

c) x³-125: The expression x³-125 is a difference of cubes, which can be factored as (a³-b³) = (a-b)(a²+ab+b²). In this case, a = x and b = 5. Hence: x³-125 = (x-5)(x²+5x+25).

Evaluating Expressions

To find the value of the expression (a-2)²+3(a-4) when a = 2, we substitute a = 2 into the expression: (2-2)² + 3(2-4) = 0² + 3(-2) = 0 - 6 = -6.

Multiplying Expressions

a) (1+3xy)(1-3xy): The given expression is a difference of squares, so it can be factored as (a+b)(a-b) where a = 1 and b = 3xy. Therefore: (1+3xy)(1-3xy) = (1)² - (3xy)² = 1 - 9x²y².

b) (2a+b)²-(2a-b)²: Expanding (2a+b)² and (2a-b)², we get: (2a+b)² = 4a² + 4ab + b², (2a-b)² = 4a² - 4ab + b². Subtracting the second from the first, we get: (2a+b)²-(2a-b)² = 8ab.

c) (x²-y³)²: The expression (x²-y³)² is a perfect square trinomial, which can be expanded as: (x²-y³)² = x