Question

Какая из точек принадлежит графику y=2x^2+12

Answer 1

Объяснение:

нет точек перегиба и нет пересечения с осью х

а с осью у у=12,т.к.

у=2×0²+12

у=12

ось симметрии х=0

Answer 2

Point Belonging to the Graph of y=2x^2+12

The graph of the equation y=2x^2+12 represents a parabola. To determine which point belongs to this graph, we can substitute specific values of x into the equation to find the corresponding y-values.

Let's calculate the y-values for a few x-values to identify a point on the graph.

Substitute x=0: y = 2(0)^2 + 12 = 12

Substitute x=1: y = 2(1)^2 + 12 = 14

Substitute x=2: y = 2(2)^2 + 12 = 20

Based on these calculations, the point (0, 12) belongs to the graph of the equation y=2x^2+12.