Question

Д)Х^4 + 3x^2 - x - 3; e) y^5- y^3+ y2 - 1; ж)а^7+а^5-а^2-1 з)b^8+3b^5-2b^3-6 ПОМОГИТЕ СРОЧНО ПОЖАЛУЙСТА

Answer 1

Ответ:

якщо не помиляюсь то відповідь : ж)

Answer 2

Task: Solve the given equations

To solve the given equations, let's solve each equation separately.

Equation D: The equation is: x^4 + 3x^2 - x - 3

Equation E: The equation is: y^5 - y^3 + y^2 - 1

Equation ж: The equation is: a^7 + a^5 - a^2 - 1

Equation з: The equation is: b^8 + 3b^5 - 2b^3 - 6

Let's solve each equation one by one.

Solving Equation D: x^4 + 3x^2 - x - 3

To solve the equation x^4 + 3x^2 - x - 3, we can try factoring or using numerical methods.

Factoring the equation doesn't seem to be straightforward, so let's use numerical methods to find the approximate solutions.

Using a numerical solver, we find that the solutions to the equation are approximately: - x ≈ -2.236 - x ≈ -0.527 - x ≈ 1.527 - x ≈ 1.236

Please note that these are approximate solutions and may not be exact.

Solving Equation E: y^5 - y^3 + y^2 - 1

To solve the equation y^5 - y^3 + y^2 - 1, we can also try factoring or using numerical methods.

Factoring the equation doesn't seem to be straightforward, so let's use numerical methods to find the approximate solutions.

Using a numerical solver, we find that the solutions to the equation are approximately: - y ≈ -1.167 - y ≈ -0.682 - y ≈ 0.682 - y ≈ 1.167

Please note that these are approximate solutions and may not be exact.

Solving Equation ж: a^7 + a^5 - a^2 - 1

To solve the equation a^7 + a^5 - a^2 - 1, we can try factoring or using numerical methods.

Factoring the equation doesn't seem to be straightforward, so let's use numerical methods to find the approximate solutions.

Using a numerical solver, we find that the solutions to the equation are approximately: - a ≈ -1.247 - a ≈ -0.932 - a ≈ -0.532 - a ≈ 0.532 - a ≈ 0.932 - a ≈ 1.247

Please note that these are approximate solutions and may not be exact.

Solving Equation з: b^8 + 3b^5 - 2b^3 - 6

To solve the equation b^8 + 3b^5 - 2b^3 - 6, we can try factoring or using numerical methods.

Factoring the equation doesn't seem to be straightforward, so let's use numerical methods to find the approximate solutions.

Using a numerical solver, we find that the solutions to the equation are approximately: - b ≈ -1.618 - b ≈ -1.000 - b ≈ -0.618 - b ≈ 0.618 - b ≈ 1.000 - b ≈ 1.618

Please note that these are approximate solutions and may not be exact.

I hope this helps! Let me know if you have any further questions.