Question

4x² - 4x - 3= 0; пожалуйста помогите

Answer 1

4x²-4x-3=0
D = b²-4ac = (-4)²-4*4*(-3) = 64 = 8²
x1=(4+8)/(2*4); x1=1,5
x2=(4-8)/(2*4); x=-0,5

Answer 2

Quadratic Equation Solution

To solve the quadratic equation 4x² - 4x - 3 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 4, b = -4, and c = -3. Let's substitute these values into the formula and solve for x.

x = (-(-4) ± √((-4)² - 4 * 4 * (-3))) / (2 * 4)

Simplifying further:

x = (4 ± √(16 + 48)) / 8

x = (4 ± √64) / 8

x = (4 ± 8) / 8

This gives us two possible solutions:

x₁ = (4 + 8) / 8 = 12 / 8 = 1.5

x₂ = (4 - 8) / 8 = -4 / 8 = -0.5

Therefore, the solutions to the quadratic equation 4x² - 4x - 3 = 0 are x = 1.5 and x = -0.5.