Question

(x+3)(x-4)-(x-2)(x+1)=5. уравнение ​

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

Объяснение:

(х + 3)(х - 4) - (х - 2)(х + 1) = 5

(х² - 4х + 3х - 12) - (х² + х - 2х - 2) = 5

(х² - х - 12) - (х² - х - 2) = 5

х² - х - 12 - х² + х + 2 = 5

-10 = 5

х Є ∅

Утверждение ложно для любого значения х

Answer 3

To solve the equation (x+3)(x-4)-(x-2)(x+1)=5, let's expand the expressions and simplify:

(x+3)(x-4) - (x-2)(x+1) = 5 (x^2 - 4x + 3x - 12) - (x^2 + x - 2x - 2) = 5 (x^2 - x - 12) - (x^2 - x - 2) = 5 x^2 - x - 12 - x^2 + x + 2 = 5 -12 + 2 = 5 -10 = 5

However, we have obtained an incorrect statement (-10 = 5), which means that there is no solution to this equation. The original equation is inconsistent, and there are no values of x that satisfy it.