Question

(36^2-1)(a-1\6a+1-a+1\6a-1) при a=100^ степень/ дробь

Answer 1

Смотри.......................

Answer 2

To simplify the expression, let's start by calculating the value of a given the expression a = 100^st/frac, where st and frac represent the numerator and denominator, respectively.

a = 100^(st/frac)

Now, we can substitute this value of a into the expression (36^2 - 1)(a - 1/6a + 1 - a + 1/6a - 1).

(36^2 - 1)(a - 1/6a + 1 - a + 1/6a - 1)

First, let's simplify the numerator (36^2 - 1).

36^2 - 1 = 1295

Now, let's substitute the value of a into the expression:

(1295)(100^(st/frac) - 1/6 * 100^(st/frac) + 1 - 100^(st/frac) + 1/6 * 100^(st/frac) - 1)

We can simplify this further by combining like terms:

(1295)(100^(st/frac) - 100^(st/frac) + 1/6 * 100^(st/frac) + 1/6 * 100^(st/frac) - 1 + 1)

Simplifying the terms inside the parentheses:

(1295)(2/6 * 100^(st/frac))

Reducing the fraction:

(1295)(1/3 * 100^(st/frac))

Multiplying the coefficients:

(1295/3 * 100^(st/frac))

Therefore, the simplified expression is (1295/3 * 100^(st/frac)).