Question

какое давление оказывает на фундамент мраморная колонна массой 6 т если площадь её основания 200 см2​

Answer 1

Ответ:

3МПа

S=200см²=0,02м²( так как 1м=100см)

м=6 т =6000кг

F=mg=6000*10=60000Н

Р=F/S

P=60000*0,02=3000000Па=3МПа

Answer 2

Calculating Pressure Exerted by a Marble Column

To calculate the pressure exerted by the marble column, we can use the formula:

Pressure (P) = Force (F) / Area (A)

Given: - Force (F) = 6 tons = 6000 kg (1 ton = 1000 kg) - Area (A) = 200 cm^2 = 0.02 m^2 (1 m^2 = 10,000 cm^2)

Calculation

Using the formula, we can calculate the pressure exerted by the marble column:

Pressure (P) = 6000 kg / 0.02 m^2

Pressure (P) = 300,000 Pa

Therefore, the pressure exerted by the marble column with a mass of 6 tons and a base area of 200 cm^2 is 300,000 Pascal.