Question

РЕШИТЕ ЗАДАЧУ,ДАМ 100 БАЛЛОВ.СРОЧНО Протон, що влетів в однорідне електричне поле напруженістю 200В/м, паралельно до ліній напруженості, зупинився, пройшовши шлях 40 см. Яка початкова швидкість протона. Відповідь надайте к км/с. Число напишіть без одиниць вимірювання

Answer 1

Ответ:

124 км/с

Объяснение:

m=1.67*10^-27 кг    E=200 В/м    d=0.4 м    q=1.6*10^-19 Кл    vo=?

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q*U=m*vo²/2    (Кинетическая энергия равна работе электрического поля)

U=E*d

vo=√(2*q*E*d/m)=√(2*1.6*10^-19*200*0.4/(1.67*10^-27))≈1.24*10^5 м/с

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Answer 2

To solve this problem, we can use the equation of motion for an object moving in a uniform electric field. The equation is:

v = u + at

Where: - v is the final velocity of the proton - u is the initial velocity of the proton - a is the acceleration of the proton - t is the time taken by the proton to travel the given distance

In this case, the proton comes to a stop after traveling a distance of 40 cm (0.4 m) in an electric field with an intensity of 200 V/m. The acceleration of the proton can be calculated using the equation:

a = E * q / m

Where: - E is the electric field intensity - q is the charge of the proton (1.6 x 10^-19 C) - m is the mass of the proton (1.67 x 10^-27 kg)

Let's calculate the acceleration first:

a = (200 V/m) * (1.6 x 10^-19 C) / (1.67 x 10^-27 kg)

Using the given values, we can calculate the acceleration of the proton.

Now, we can use the equation of motion to find the initial velocity of the proton. Since the proton comes to a stop, the final velocity (v) is 0 m/s. We know the acceleration (a) and the distance (s) traveled by the proton, which is 0.4 m. Rearranging the equation, we get:

v = u + at

Since v = 0, we can solve for u:

0 = u + (a * t)

u = - (a * t)

Now, we can substitute the values of a and t to find the initial velocity (u) of the proton.

Let's calculate the values and find the answer.