Question

Шарик, скатываясь с наклонного желоба из состояния покоя, за 3 секунды прошёл путь 0,9 м. Считая движение шарика равноускоренным, определить в СИ его ускорение. пожалуйста с рисунком ​

Answer 1

Ответ:

.....................................................

Answer 2

Problem Statement

We are given that a ball rolls down a sloping chute from a state of rest and covers a distance of 0.9 m in 3 seconds. We are asked to determine the acceleration of the ball in SI units.

Solution

To solve this problem, we can use the kinematic equation that relates distance, initial velocity, time, and acceleration:

\[distance = initial\ velocity \times time + \frac{1}{2} \times acceleration \times time^2\]

In this case, the ball starts from rest, so the initial velocity is 0. We are given that the distance covered by the ball is 0.9 m and the time taken is 3 seconds. Plugging these values into the equation, we can solve for the acceleration.

\[0.9 = 0 \times 3 + \frac{1}{2} \times acceleration \times 3^2\]

Simplifying the equation:

\[0.9 = \frac{9}{2} \times acceleration\]

Solving for acceleration:

\[acceleration = \frac{2 \times 0.9}{9} = 0.2 \, \text{m/s}^2\]

Therefore, the acceleration of the ball is 0.2 m/s^2.


Please note that the provided search result snippet does not contain any relevant information for this specific problem. The solution is derived using the kinematic equation and the given information.