Question

1. Решите задачу: Ариф, неподвижно стоящий на эс- калаторе метро, проезжает расстояние между соседними светильниками за 4 секунды. Рассто- яние между двумя соседними светильниками равно 3 метрам. Определите, с какой скоростью эска- латор поднимает Арифа. срочно заранее блогадарю​

Answer 1

Скорость 12  порополвл

Answer 2

Problem Analysis

To solve this problem, we need to determine the speed at which the escalator is carrying Arif. We are given that Arif travels the distance between two adjacent light fixtures in 4 seconds, and the distance between the fixtures is 3 meters. We can use this information to calculate the speed of the escalator.

Solution

Let's assume the speed of the escalator is v meters per second. Since Arif is standing still on the escalator, his speed relative to the ground is the sum of his speed relative to the escalator and the speed of the escalator itself.

Arif's speed relative to the escalator is 0 meters per second because he is not moving relative to the escalator. Therefore, his speed relative to the ground is equal to the speed of the escalator.

We can use the formula speed = distance / time to calculate the speed of the escalator. The distance between the light fixtures is 3 meters, and Arif takes 4 seconds to travel this distance. Therefore, the speed of the escalator is:

v = distance / time = 3 meters / 4 seconds = 0.75 meters per second

So, the escalator is carrying Arif at a speed of 0.75 meters per second.

Conclusion

Arif is being carried by the escalator at a speed of 0.75 meters per second.