Question

  2. Газ объёмом 5 м3 расширился при постоянном давлении 104кПа в 11 раз. Найти работу газа в МДж. ПОМОГИТЕ ПОЖАЛУЙСТА У МЕНЯ СОЧ ДАМ 50 БАЛЛОВ​

Answer 1

Ответ:

5.2*10⁶ Дж

Объяснение:

V1=5 м³    p=104*10³  Па   V2=11*V1    A=?

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A=pΔV=p*10*V1=104*10³*10*5=5.2*10⁶ Дж

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Answer 2

To find the work done by a gas, we can use the formula:

Work = Pressure x Change in Volume

In this case, the gas initially has a volume of 5 m^3 and expands to 11 times its initial volume. The pressure remains constant at 104 kPa.

Let's calculate the change in volume:

Change in Volume = Final Volume - Initial Volume

Change in Volume = 11 x Initial Volume - Initial Volume

Change in Volume = 10 x Initial Volume

Substituting the values:

Change in Volume = 10 x 5 m^3 = 50 m^3

Now, we can calculate the work done by the gas:

Work = Pressure x Change in Volume

Work = 104 kPa x 50 m^3

To convert the work from kilopascals (kPa) to megajoules (MJ), we need to use the conversion factor:

1 kPa = 0.01 MJ

Substituting the values:

Work = 104 kPa x 50 m^3 x 0.01 MJ/kPa

Work = 52 MJ

Therefore, the work done by the gas is 52 megajoules (MJ).