Question

3. Два свинцовых шара массами m1 = 100 г и m2 = 400 г движутся навстречу друг другу со скоростями V1 = 1 м/с и V2 = 2 м/с. Какую скорость будут иметь шары после их слипания?С объяснением!

Answer 1

Ответ:

Вот держи

Объяснение:

Answer 2

Calculation of Post-Collision Velocity

To calculate the velocity of the two spheres after they collide, we can use the principle of conservation of momentum. According to this principle, the total momentum of an isolated system remains constant if no external forces act on it.

The formula to calculate the post-collision velocity of the two spheres is given by:

Vf = (m1\*V1 + m2\*V2) / (m1 + m2)

Where: - Vf is the final velocity of the spheres after collision - m1 and m2 are the masses of the spheres - V1 and V2 are the velocities of the spheres before collision

Calculation

Using the given values: - m1 = 100 g = 0.1 kg - m2 = 400 g = 0.4 kg - V1 = 1 m/s - V2 = 2 m/s

We can substitute these values into the formula to find the final velocity:

Vf = (0.1 kg * 1 m/s + 0.4 kg * 2 m/s) / (0.1 kg + 0.4 kg)

Vf = (0.1 + 0.8) / 0.5

Vf = 0.9 / 0.5

Vf = 1.8 m/s

Conclusion

After the collision, the two spheres will have a combined velocity of 1.8 m/s in the direction of the initial motion of the 400 g sphere.

This calculation is based on the principle of conservation of momentum, which states that the total momentum of an isolated system remains constant. The sources provided support the use of this principle in the context of the given problem.