Question

Условие задания: Найди, на сколько сантиметров удлинится пружина под действием силы 4,25 н. Коэффициент жёсткости пружины равен 25 H/м Ответ: пружина удлинится на … см.

Answer 1

Ответ:

Объяснение:

F=kx

x=F/k=4.25/25=0.17 м=17 см

Answer 2

Ответ:

x=kx

x=f/x=4.25/25=0.17

M=17cm

Answer 3

Calculation of Spring Extension

To calculate the extension of the spring under the given force and stiffness coefficient, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the extension of the spring. The formula for Hooke's Law is:

F = kx

Where: - F = force applied to the spring (in newtons) - k = stiffness coefficient of the spring (in newtons per meter) - x = extension of the spring (in meters)

We can rearrange the formula to solve for the extension x:

x = F / k

Given: - Force F = 4.25 N - Stiffness coefficient k = 25 N/m

Calculation

Using the given values, we can calculate the extension of the spring:

x = 4.25 N / 25 N/m

x ≈ 0.17 m

So, the spring will extend by approximately 0.17 meters under the given force of 4.25 N and with a stiffness coefficient of 25 N/m.