Question

На менший поршень гідравлічної машини, площа якого 5 см2, діє сила 4Н. Яку силу тиску буде створювати більший поршень, площа якого 150 см2? Срочно у нас кр Пж

Answer 1

Ответ: 120Н

Объяснение:

Дано:

S1=5см²

F1=4Н

S2=150см²

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F2-?

F1/S1=F2/S2

F2=F1*S2/S1=4*150/5=120Н

Answer 2

Calculation of Pressure in Hydraulic System

To calculate the force exerted by the larger piston in the hydraulic system, we can use the formula for pressure:

Pressure = Force / Area

Given: - Force on the smaller piston = 4 N - Area of the smaller piston = 5 cm^2 - Area of the larger piston = 150 cm^2

First, let's calculate the pressure exerted by the smaller piston:

Pressure = Force / Area Pressure = 4 N / 5 cm^2 Pressure = 0.8 N/cm^2

Now, we can use the pressure exerted by the smaller piston to calculate the force exerted by the larger piston:

Force = Pressure × Area Force = 0.8 N/cm^2 × 150 cm^2 Force = 120 N

Therefore, the force exerted by the larger piston will be 120 N.