Question

4. Решите системы линейных уравнений с двумя переменными способом сложения: {3x-2y-6=0{6x+2y-30=0​ Смотреть ответ Grineva2005 Grineva2005 (3х-2у-6)+(6х+2у-30)=09х-36=0х=43(4)-2у-6=0у=3х=4, у=3 Пасяба ;) Да это правильно? Ставрополь Ты крутая,может когда-нибудь встретимся,где ты живёшь?

Answer 1

Solving Systems of Linear Equations by Addition Method

To solve the system of linear equations using the addition method, we need to eliminate one variable by adding the equations together. Let's solve the given system of equations step by step:

The system of equations is: 1. 3x - 2y - 6 = 0 2. 6x + 2y - 30 = 0

To eliminate the variable "y," we can add the two equations together. Adding the left sides and the right sides of the equations separately, we get:

(3x - 2y - 6) + (6x + 2y - 30) = 0 + 0

Simplifying the equation, we have:

9x - 36 = 0

Now, let's solve for "x":

9x = 36

Dividing both sides of the equation by 9, we find:

x = 4

Now that we have the value of "x," we can substitute it back into one of the original equations to solve for "y." Let's use the first equation:

3(4) - 2y - 6 = 0

12 - 2y - 6 = 0

Simplifying the equation, we have:

-2y + 6 = 0

Subtracting 6 from both sides of the equation, we find:

-2y = -6

Dividing both sides of the equation by -2, we get:

y = 3

Therefore, the solution to the system of equations is x = 4 and y = 3.

I hope this helps! Let me know if you have any further questions.