Question

1) (a–3)²–a(6+a) при a= –1/12​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Сначала упростим выражение:

(a-3)2-a(6+a)=a2-6a+9-6a-a2=9-12a

Теперь подставляем значение а:

9-12×(-1/12)=9+1=10

Ответ: 10

Answer 3

To evaluate the expression (a–3)²–a(6+a) when a = –1/12, we need to substitute the value of a into the expression and perform the calculations step-by-step.

Let's proceed with the calculation:

Step 1: Substitute a with –1/12 in the expression (a–3)²–a(6+a)

Expression = ((–1/12)–3)² – (–1/12)(6 – 1/12)

Step 2: Simplify inside the parentheses

Expression = (–37/12)² – (–1/12)(71/12)

Step 3: Square the fraction (–37/12)²

Expression = (1369/144) – (–71/144)

Step 4: Subtract fractions

Expression = (1369/144) + (71/144)

Step 5: Add fractions with a common denominator

Expression = (1369 + 71) / 144

Step 6: Perform the final calculation

Expression = 1440 / 144

Step 7: Reduce the fraction if possible

Expression = 10

So, when a = –1/12, the expression (a–3)²–a(6+a) evaluates to 10.