Question

5x⁶-3x²+7-2x⁶-3x⁶+4x² при x=-10 приведите в стандартный вид

Answer 1

Приведём многочлен к стандартному виду:

$5x^6-3x^2+7-2x^6-3x^6+4x^2=(5-2-3)x^6+(4-3)x^2+7=\\\\=0*x^6+1*x^2+7=x^2+7$

Найдём значение полученного выражения при х= -10

$x^2+7=(-10)^2+7=100+7=107$

Answer 2

Ответ:107

Пошаговое объяснение

5x⁶-3x²+7-2x⁶-3x⁶+4x² считаем = х2+7

подставляем -10 и будет 100+7 = 107

Answer 3

To simplify the expression and put it in standard form, we need to combine like terms by performing addition and subtraction. The expression is:

5x⁶ - 3x² + 7 - 2x⁶ - 3x⁶ + 4x²

Now, let's combine the terms with the same exponent:

(5x⁶ - 2x⁶ - 3x⁶) + (-3x² + 4x²) + 7

When we combine the x⁶ terms, we get:

(5 - 2 - 3)x⁶ + (-3 + 4)x² + 7

Simplifying further:

0x⁶ + 1x² + 7

Since the coefficient of x⁶ is zero, we can remove that term, leaving us with:

x² + 7

Now, we need to find the value of this expression when x = -10:

(-10)² + 7

(-10)² = 100

Now, add 7 to it:

100 + 7 = 107

So, when x = -10, the expression x² + 7 simplifies to 107.