Question

Помогите, пожалуйста, срочно решить: На гранях игрального кубика написаны числа 7, 8, 9,10,11,12. Кубик бросили дважды. В первый раз сумма чисел на четырех «вертикальных» (то есть кроме нижней и верхней) гранях была равна 37, а во второй раз — 38. Какое число может быть написано на грани, противоположной грани с числом 11? Найдите все возможные варианты.

Answer 1

Ответ:

18

Пошаговое объяснение:

или 12

Answer 2

Problem Analysis

We are given a six-sided die with the numbers 7, 8, 9, 10, 11, and 12 written on its faces. The die is rolled twice, and the sum of the numbers on the four "vertical" faces (excluding the top and bottom faces) is 37 in the first roll and 38 in the second roll. We need to determine which number could be written on the face opposite the face with the number 11.

Solution

Let's analyze the problem step by step:

1. In the first roll, the sum of the numbers on the four vertical faces is 37. We need to find the possible combinations of numbers that add up to 37. We can start by listing all the possible combinations:

- 7 + 8 + 9 + 10 = 34 - 7 + 8 + 9 + 11 = 35 - 7 + 8 + 9 + 12 = 36 - 7 + 8 + 10 + 11 = 36 - 7 + 8 + 10 + 12 = 37 - 7 + 8 + 11 + 12 = 38 - 7 + 9 + 10 + 11 = 37 - 7 + 9 + 10 + 12 = 38 - 7 + 9 + 11 + 12 = 39 - 7 + 10 + 11 + 12 = 40 - 8 + 9 + 10 + 11 = 38 - 8 + 9 + 10 + 12 = 39 - 8 + 9 + 11 + 12 = 40 - 8 + 10 + 11 + 12 = 41 - 9 + 10 + 11 + 12 = 42

From the above combinations, we can see that the sum of the numbers on the four vertical faces can only be 34, 35, 36