Question

складіть рівняння прямої що проходить через точку М(-3;1) і утворює з додатним напрямом осі абсцис кут 135°

Answer 1

Відповідь: у=-х-2

Пояснення:

розв'язання завдання додаю

Answer 2

Equation of a Line Passing Through Point M(-3,1) and Forming an Angle of 135° with the Positive x-axis

To find the equation of a line that passes through the point M(-3,1) and forms an angle of 135° with the positive x-axis, we can use the slope-intercept form of a linear equation, which is given by:

y = mx + b

where: - m is the slope of the line, and - b is the y-intercept of the line.

To determine the slope of the line, we can use the fact that the line forms an angle of 135° with the positive x-axis. The slope of a line can be calculated using the tangent of the angle between the line and the positive x-axis.

The tangent of 135° is equal to -1. Therefore, the slope of the line is -1.

Now that we have the slope, we can substitute the coordinates of the point M(-3,1) into the equation to find the y-intercept.

Substituting x = -3, y = 1, and m = -1 into the equation y = mx + b, we can solve for b:

1 = -1 * (-3) + b 1 = 3 + b b = 1 - 3 b = -2

Therefore, the equation of the line that passes through the point M(-3,1) and forms an angle of 135° with the positive x-axis is:

y = -x - 2.

Please let me know if there's anything else I can help you with!