Question

Даны векторы a -1,2,8 и b 2,-4,3.Найдите координаты вектора -3a+2b

Answer 1

a(-1; 2; 8)

b(2; -4; 3)

- 3a + 2b = - 3(-1; 2; 8) + 2(2; -4; 3) = (3; -6; -24) + (4; -8; 6) = (7; -14; -18)

Answer 2

To find the coordinates of the vector -3a + 2b, we need to first calculate -3a and 2b, and then add them together.

Given vectors: a = <-1, 2, 8> b = <2, -4, 3>

Let's calculate -3a: -3a = -3 * <-1, 2, 8> = <(-3) * (-1), (-3) * 2, (-3) * 8> = <3, -6, -24>

Next, let's calculate 2b: 2b = 2 * <2, -4, 3> = <2 * 2, 2 * (-4), 2 * 3> = <4, -8, 6>

Now, let's add the vectors -3a and 2b together to find -3a + 2b: -3a + 2b = <3, -6, -24> + <4, -8, 6> = <3 + 4, -6 - 8, -24 + 6> = <7, -14, -18>

So, the coordinates of the vector -3a + 2b are <7, -14, -18>.