Question

Найдите cos a tg a если sin a 1/6​

Answer 1

Ответ:

lol

Объяснение:

Cos a=sqrt(1-sin^2a)=sqrt(1-1/36)=sqrt35/6

Tg a=sin a/cos a

Tg a=1/sqrt(35)=sqrt35/35

Answer 2

To find cos(a) and tan(a) when sin(a) = 1/6, we can use the Pythagorean trigonometric identity and the definition of tangent. Here's how:

Given that sin(a) = 1/6, we can use the Pythagorean identity to find cos(a):

sin^2(a) + cos^2(a) = 1

Substitute sin(a) = 1/6 into the equation:

(1/6)^2 + cos^2(a) = 1 1/36 + cos^2(a) = 1 cos^2(a) = 1 - 1/36 cos^2(a) = 35/36

Now, to find the value of cos(a), take the square root of both sides:

cos(a) = ±√(35/36)

Since cosine is positive in the first and fourth quadrants, we take the positive square root:

cos(a) = √(35/36) = √35/6

Next, we'll find tan(a) using the definition of tangent:

tan(a) = sin(a) / cos(a)

Substitute sin(a) = 1/6 and cos(a) = √35/6:

tan(a) = (1/6) / (√35/6)

To simplify, multiply both the numerator and denominator by 6:

tan(a) = 1 / √35

To rationalize the denominator, multiply the numerator and denominator by √35:

tan(a) = (√35) / (35)

So, the values of cos(a) and tan(a) when sin(a) = 1/6 are:

cos(a) = √35/6 tan(a) = (√35) / 35