Question

В треугольнике ABC провели биссектрису AA1 угла BAC. Оказалось, что угол BAC=3*угол ABC. Найдите величину угла BAC, если угол ACB=48 градусам. Прошу помочь!!!

Answer 1

Ответ:

99 градусов

Объяснение:

Непонятно причем здесь биссектриса АА1.

у-л ВАС=3 * у-л АВС

Пусть угол АВС=в

3в+в=180-48

4в=132

в=33 гр

Угол  ВАС=3*33=99 градусов

Answer 2

Problem Analysis

We are given a triangle ABC, where the angle ACB is 48 degrees. We are also told that the angle BAC is three times the angle ABC. We need to find the measure of angle BAC.

Solution

Let's assume that the measure of angle ABC is x degrees. According to the given information, the measure of angle BAC is three times the measure of angle ABC, so it is 3x degrees.

Since the sum of the angles in a triangle is always 180 degrees, we can write the equation:

x + 3x + 48 = 180

Simplifying the equation, we have:

4x + 48 = 180

Subtracting 48 from both sides, we get:

4x = 132

Dividing both sides by 4, we find:

x = 33

Therefore, the measure of angle ABC is 33 degrees, and the measure of angle BAC is three times that, which is 3 * 33 = 99 degrees.

So, the measure of angle BAC is 99 degrees.

Conclusion

In triangle ABC, with angle ACB measuring 48 degrees, the measure of angle BAC is found to be 99 degrees.