Question

4x^2 - 16 = 0 3x^2 - x = 0 помогите с матаном(

Answer 1

1) 4x² -16 =0
(2x -4)(2x +4) =0
2x -4 =0, 2x =4, x =2
2x +4 =0, 2x= -4, x= -2
или
4x² =16, x² =4, x=+-2
ответ: x= -2, x =2

2) 3x² -x =0
x(3x -1) =0
x =0
3x -1 =0, 3x =1, x =1/3
ответ: x =0, x =1/3

Answer 2

I can help you solve these equations by factoring. Here are the steps:

- For the equation 4x^2 - 16 = 0, we can factor out 4 from both terms on the left side. This gives us 4(x^2 - 4) = 0. - Next, we can use the difference of squares formula to factor x^2 - 4 as (x + 2)(x - 2). This gives us 4(x + 2)(x - 2) = 0. - To find the values of x that make this equation true, we need to set each factor equal to zero and solve for x. This gives us x + 2 = 0 or x - 2 = 0. - Solving for x, we get x = -2 or x = 2. These are the two solutions of the equation.

- For the equation 3x^2 - x = 0, we can factor out x from both terms on the left side. This gives us x(3x - 1) = 0. - To find the values of x that make this equation true, we need to set each factor equal to zero and solve for x. This gives us x = 0 or 3x - 1 = 0. - Solving for x, we get x = 0 or x = 1/3. These are the two solutions of the equation.

I hope this helps you with your math. You can also check out some online resources that can solve equations by factoring, such as [this one](https://quickmath.com/solve/) or [this one](https://www.mathway.com/popular-problems/Algebra/246260). You can also find some answers to similar problems [here](https://online-otvet.ru/algebra/5cea921a96f4e19a293abd15).