Question

21x в третьей степени y во второй степени *(- 4/7x) Помогите пожалуйста привести одночлен к стандартному виду.

Answer 1

21x^3y^2*(-4/7x)=-12x^2y^2

(4/7x)   x у тебя в знаменателе?

Answer 2

Converting a Monomial to Standard Form

To convert the given monomial to standard form, we can start by simplifying the expression step by step.

The given monomial is: 21x^3y^2 * (-4/7x)

First, let's simplify the expression by multiplying the coefficients and adding the exponents of the variables.

The coefficient of the monomial is 21, and the coefficient of the second term is -4/7. Multiplying these coefficients gives us -12.

The variables in the monomial are x and y. The exponent of x in the first term is 3, and in the second term, it is 1. Adding these exponents gives us 4. The exponent of y in the first term is 2, and there is no y in the second term, so the exponent of y remains 2.

So, the simplified expression is: -12x^4y^2

Therefore, the given monomial 21x^3y^2 * (-4/7x), when converted to standard form, is -12x^4y^2.