Question

сколько корней имеет уравнение 4y^2+my-5=0?

Answer 1

4y^2+my-5=0

D=b^2-4ac=m^2+4*4*5=m^2+80

так как (m^2+80) больше чем 0,то уравнение имеет 2 корня

Answer 2

Solving the Quadratic Equation 4y^2 + my - 5 = 0

To find the number of roots of the quadratic equation 4y^2 + my - 5 = 0, we can use the discriminant formula. The discriminant (denoted as Δ) of a quadratic equation ax^2 + bx + c = 0 is given by the formula:

Δ = b^2 - 4ac

If the discriminant is greater than 0, the equation has two distinct real roots. If the discriminant is equal to 0, the equation has one real root. If the discriminant is less than 0, the equation has no real roots.

Calculating the Discriminant for the Given Quadratic Equation

For the equation 4y^2 + my - 5 = 0, the coefficients are: - a = 4 - b = m - c = -5

Using the discriminant formula, the discriminant Δ is given by: Δ = m^2 - 4 * 4 * (-5) Δ = m^2 + 80

Conclusion

The number of roots of the quadratic equation 4y^2 + my - 5 = 0 depends on the value of the discriminant Δ. If Δ > 0, the equation has two distinct real roots. If Δ = 0, the equation has one real root. If Δ < 0, the equation has no real roots.

Unfortunately, the search results provided do not contain the specific value of the discriminant for the given equation. Therefore, without the specific value of 'm', it is not possible to determine the number of roots of the given quadratic equation.