Question

Как решить систему уравнений 2x-3y=-4 ; 3х+2у=7

Answer 1

2х=-4+3у
х=-2+1,5у
3(-2+1.5у)+2у=7
-6+4,5у+2у=7
6,5у=7+6
6,5у=13
у=2
х=1

Answer 2

{2x-3y=-4|*2
{3x+2y=7|*3
+{4x-6y=-8
+{9x+6y=21
13x=13:13
x=1
2*1-3y=-4
-3y=-4-2
-3y=-6:(-3)
y=2

Answer 3

Solving the System of Equations 2x-3y=-4 and 3x+2y=7

To solve the system of equations 2x-3y=-4 and 3x+2y=7, we can use the method of substitution or elimination. Let's use the method of substitution to solve this system.

First, let's solve one of the equations for one variable in terms of the other and then substitute that expression into the other equation.

We'll start with the equation 2x-3y=-4.

Solving for x in terms of y:

2x = 3y - 4 x = (3y - 4)/2

Now, we'll substitute this expression for x into the second equation 3x+2y=7.

Substituting x:

3((3y - 4)/2) + 2y = 7 9y - 12 + 2y = 7 11y - 12 = 7 11y = 19 y = 19/11

Now that we have found the value of y, we can substitute it back into the expression for x to find the value of x.

Substituting y:

x = (3(19/11) - 4)/2 x = (57/11 - 4)/2 x = (57/11 - 44/11)/2 x = 13/11/2 x = 13/22

So, the solution to the system of equations 2x-3y=-4 and 3x+2y=7 is: x = 13/22 and y = 19/11.