Question

Как решить пример (3-x) (x+5)=0 Заранее спасибо,и пожалуйста помогите.Срочно надо!!

Answer 1

Х=3
(3-3=0) умножить на (3+5=8). Значит 0 умножаем на 8 и получаем 0.

Answer 2

3-х=0 и х+5=0
-х=-3    х=-5
х=3      х=-5

Answer 3

Solving the Equation (3-x)(x+5)=0

To solve the equation (3-x)(x+5)=0, we can use the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero. Let's solve the equation step by step.

First, expand the equation: (3-x)(x+5)=0 3x + 15 - x^2 - 5x = 0 -x^2 - 2x + 15 = 0

Now, we have a quadratic equation in the form of ax^2 + bx + c = 0. We can solve for x using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = -1, b = -2, and c = 15. Plugging these values into the quadratic formula, we get: x = (-(-2) ± √((-2)^2 - 4*(-1)*15)) / (2*(-1)) x = (2 ± √(4 + 60)) / (-2) x = (2 ± √64) / (-2) x = (2 ± 8) / (-2)

So, the solutions for x are: x = (2 + 8) / (-2) = 10 / (-2) = -5 x = (2 - 8) / (-2) = -6 / (-2) = 3

Therefore, the solutions to the equation (3-x)(x+5)=0 are x = -5 and x = 3.

I hope this helps! If you have any further questions, feel free to ask.