Question

Lx-2l lx 3l=5 очень надо Решите пожалуйста

Answer 1

$|x-2|+|x+3|=5$
ОДЗ:
$\left \{ {{x-2 \geq 0} \atop {x+3 \geq 0}} \right.$
$\left \{ {{x \geq 2} \atop {x \geq -3}} \right.$
$x-2+x+3=5$
$x=2$

$\left \{ {{x-2 < 0} \atop {x+3 < 0}} \right.$
$\left \{ {{x < 2} \atop {x < -3}} \right.$
$-x+2-x-3=5$
$x=-3$
Условие не выполняется, поэтому -3 не является корнем уравнения.

Ответ: 2

Answer 2

Solving the Equation

To solve the equation Lx - 2|l| + |lx + 3|l| = 5, we can follow these steps:

1. First, we need to identify the absolute value expressions and solve for both positive and negative cases. 2. Then, we can substitute the solutions back into the original equation to verify.

Let's start by solving for the absolute value expressions.

Solving for Absolute Value Expressions

The absolute value of a number is its distance from 0 on the number line. When solving absolute value equations, we consider both the positive and negative cases.

For the absolute value expression |lx + 3|l|, we can consider two cases: 1. When lx + 3 is positive: lx + 3 = lx + 3 2. When lx + 3 is negative: -(lx + 3) = lx + 3

Similarly, for the absolute value expression -2|l|, we can consider two cases: 1. When l is positive: -2l = -2l 2. When l is negative: -2(-l) = -2l

Substituting Solutions Back

After solving for the absolute value expressions, we can substitute the solutions back into the original equation to verify.

Let's proceed with solving for the absolute value expressions and then substitute the solutions back into the original equation.