Question

Представить квадрат двучлена (11+6p)^2 в виде многочлена

Answer 1

11^2+2*11*6p+(6p)^2=121+132p+36p^2

Answer 2

$(11+6p)^2=(11+6p)*(11+6p)=121+22*6p+36p^2$
$=121+132p+36p^2$