Question

Подайте у вигляді многочлена вирази: 1)(с-6)2 2)(2а-3b)2 3)(5-a)(5+a) Пожалуста

Answer 1

1) (c-6)² = c² - 12c + 36

2) (2а-3b)² = 4a² - 12ab + 9b²

3) (5-a)(5+a) = 25 - 5a + 5a - a² = 25 - a²

Answer 2

1) (с-6)^2: To expand the expression (с-6)^2, we can use the formula for squaring a binomial, which is (a-b)^2 = a^2 - 2ab + b^2. In this case, a = с and b = 6. Plugging in these values, we get:

(с-6)^2 = с^2 - 2(с)(6) + 6^2

Simplifying further, we have:

(с-6)^2 = с^2 - 12с + 36

2) (2а-3b)^2: To expand the expression (2а-3b)^2, we can again use the formula for squaring a binomial. In this case, a = 2а and b = 3b. Plugging in these values, we get:

(2а-3b)^2 = (2а)^2 - 2(2а)(3b) + (3b)^2

Simplifying further, we have:

(2а-3b)^2 = 4а^2 - 12ab + 9b^2

3) (5-a)(5+a): To expand the expression (5-a)(5+a), we can use the formula for multiplying two binomials, which is (a-b)(a+b) = a^2 - b^2. In this case, a = 5 and b = a. Plugging in these values, we get:

(5-a)(5+a) = (5)^2 - (a)^2

Simplifying further, we have:

(5-a)(5+a) = 25 - a^2

So, the expressions in the form of polynomials are: 1) (с-6)^2 = с^2 - 12с + 36 2) (2а-3b)^2 = 4а^2 - 12ab + 9b^2 3) (5-a)(5+a) = 25 - a^2