Question

Найти координаты вершины параболы 2x2+12x-14 (очень срочно)

Answer 1

$x_v = \frac{-b}{2a} ; \\ x_v= \frac{-12}{4} =-3 \\ y_v = 2x_v^2+12x_v-14=2*(-3)^2+12*(-3)-14=-32$

Answer 2

Finding the Vertex of a Parabola

To find the coordinates of the vertex of the parabola given by the equation 2x^2 + 12x - 14, we can use the formula for the x-coordinate of the vertex, which is given by x = -b/2a. In this equation, a represents the coefficient of the x^2 term, and b represents the coefficient of the x term.

In the given equation, a = 2 and b = 12. Plugging these values into the formula, we get:

x = -12 / (2 * 2) = -12 / 4 = -3

Now, to find the y-coordinate of the vertex, we substitute the x-coordinate (-3) back into the original equation:

y = 2(-3)^2 + 12(-3) - 14 = 18 - 36 - 14 = -32

Therefore, the coordinates of the vertex of the parabola 2x^2 + 12x - 14 are (-3, -32).